In C++, there are a number of ways to provide Boolean tests for classes. Such support is either provided to make usage intuitive, to support generic programming, or both. We shall examine four popular ways of adding support for the popular and idiomatic if (object) {}
construct. To conclude, we will discuss a new solution, without the pitfalls and dangers of the other four. Let the games begin.
Some types, for example pointers, allow us to test their validity in Boolean contexts. Any rvalue of arithmetic, enumeration, pointer, or pointer to member type, can be implicitly converted to an rvalue of type bool
. We frequently use this property to select a branch of code to execute, for example when acquiring a resource:
if (some_type* p=get_some_type()) { // p is valid, use it } else { // p is not valid, take proper action }
Of course, such usage is not only useful for built-in types; any type with an unambiguous meaning of validity could greatly benefit from such a Boolean conversion. The alternative is to use a member function for testing. As an example, consider testing a smart pointer (without an implicit conversion to the contained pointer) for validity:
smart_ptr<some_type> p(get_some_type()); if (p.is_valid()) { // p is valid, use it } else { // p is not valid, take proper action }
Besides being more verbose, this version differs from the previous in that the name p needs to be declared outside of the scope in which it is used. This is bad from a maintenance perspective. Also, the name is_valid
will probably differ depending on the type of smart pointer at use�it can just as well be is_empty
, Empty
, Valid
, or any other name a creative designer might have thought of when creating it. Finally, even when disregarding the naming issue and the problem with declaration scope, for smart pointers there's the very real requirement to support pointer-like use. It should typically be possible to convert existing code to make use of smart pointers rather than raw pointers, with a minimum of change to the code base, e.g., code like this should work regardless of pointer smartness:
template <typename T> void some_func(const T& t) { if (t) t->print(); }
Without some conversion to a Boolean testable type, the above if
-statement won't compile for smart pointers. The goal that we set out to accomplish in this article is making that conversion safe. As we shall see, that's a bit harder than one would imagine at first glance.
operator bool
This classical approach has a straightforward implementation. I'll use the same class (Testable
) throughout this article, as seen in the following code:
// operator bool version class Testable { bool ok_; public: explicit Testable(bool b=true):ok_(b) {} operator bool() const { return ok_; } }; // operator! version class Testable { bool not_ok_; public: explicit Testable(bool b=true):not_ok_(!b) {} bool operator!() const { return not_ok_; } }; // operator void* version class Testable { bool ok_; public: explicit Testable(bool b=true):ok_(b) {} operator void*() const { return ok_==true ? this : 0; } }; // nested class version class Testable { bool ok_; public: explicit Testable(bool b=true):ok_(b) {} class nested_class {}; operator const nested_class*() const { return ok_ ? reinterpret_cast<const nested_class*>(this) : 0; } };
Note the implementation for the conversion function:
operator bool() const { return ok_; }
Now, we can use instances of the class in expressions like this:
Testable test; if (test) std::cout << "Yes, test is working!\n"; else std::cout << "No, test is not working!\n";
That's fine, but there's a nasty caveat to this as the conversion function has just told the compiler that it's free to do things behind our backs (lesson 0: never trust a compiler to do your job for you; at least not to do it properly);
test << 1; int i=test;
These are both nonsense operations, but yet allowed and legal C++ (we also have the issue of overloading to consider, which makes things even worse). So, operator bool
is not a very good approach. We're also able to compare any types that utilize this technique with each other, although that rarely makes sense:
Testable a; AnotherTestable b; if (a==b) { } if (a<b) { }
What else can we do? Well, one improvement is to add another (private) conversion function to an integral type, and thereby disallow the nonsensical operations, even those for equality and ordering. Simply declaring a private conversion function to int
does the trick. However, some drawbacks remain, making the solution less than satisfactory. The error messages when a user invokes the ambiguity aren't consistent, or readable. Also, these conversion functions may interfere with perfectly valid conversions and overloads. So we must look elsewhere for a clean solution to this problem.
operator!
It's time to move on to safer ground, through operator!
. Programmers are already accustomed to using this unary logical negation operator in Boolean contexts, which is a desirable property for intuitive usage. Still, some users might not be ready for what some people call the double-bang trick (see below), which is a requirement for checking the "good state" of such an object. The implementation is trivial:
bool operator!() const { return !ok_; }
This is a much better approach—no more implicit conversion or overloading issues to worry about, and two idiomatic ways of testing Testable
:
Testable test; if (!!test) std::cout << "Yes, test is working!\n"; if (!test2) { std::cout << "No, test2 is not working!\n";
The first version utilizes a useful trick: if (!!test)
. It's sometimes called the double-bang trick [1], but alas, it is not nearly as elegant or straightforward as if (test)
. [Editor's note: This is an old C trick used to map non-zero values to the number 1 so you can have numeric integer values map into a binary-valued index (0 or 1) for use with an array of size two] This is a pity, because if people don't understand how something works it really doesn't matter whether it's safe or not. It's still a very useful technique, but it will typically be used in library code, where �ordinary� users never see it. Of course, it's still possible to compare different types, just as was the case with the first approach (although the obscure syntax should make it obvious that it rarely makes sense to do so). Are there better ways than this?
operator void*
Here's a clever idea—using a conversion function to void*
. It's clever because there aren't that many things you can do with a void*
except test it in Boolean contexts. Here's how it works:
operator void*() const { return ok_==true ? this : 0; }
Another trivial implementation! Don't worry, from here on nothing's trivial... As you might have guessed, this solution is flawed, too. The problem is that it is now possible to do this:
Testable test; delete test;
Ouch! If you think that this situation can be saved with a little const
trickery, think again: The C++ Standard explicitly allows delete expressions with pointers to const
types [2]. Perhaps the best-known use of this technique comes from the C++ Standard� the conversion that allows the state of iostreams to be queried uses it. However, while the intention is this;
if (std::cout) { // Is the stream ok? }
it is also quite possible to do this;
std::cout << std::cin << std::cout;
Also, using a conversion like this means that it is possible to test instances of different types in Boolean contexts (all types that utilize this flawed idiom). So, it's time to get radical, and travel deeper into C++ territory.
class Testable { bool ok_; public: explicit Testable(bool b=true):ok_(b) {} class nested_class; operator const nested_class*() const { return ok_ ? reinterpret_cast<const nested_class*>(this) : 0; } };
Now, this version supports Boolean tests, but alas, too much so. We're now able to write erroneous things like this:
Testable b1,b2; if (b1==b2) { } if (b1<b2) { }
We could poison all operators that have been enabled by the conversion to make the algorithm a better fit for our purposes, but there's an even better way.
class Testable { bool ok_; typedef void (Testable::*bool_type)() const; void this_type_does_not_support_comparisons() const {} public: explicit Testable(bool b=true):ok_(b) {} operator bool_type() const { return ok_==true ? &Testable::this_type_does_not_support_comparisons : 0; } };
Simple, eh? Let's examine what's going on here. First, we typedef bool_type
to be a pointer to a const
member function of Testable
, taking zero arguments and returning void
. This is our magic type that allows for testing in Boolean contexts, without taking part in overloading contexts. Next, we define a conversion function to bool_type
, just as we did with bool
and void*
earlier. Finally, we return "true" using a pointer to a member function (this_type_does_not_support_comparisons
), which fits the bool_type
, and a null value for "false". It's now possible to safely test instances of Testable
in Boolean contexts. The strange name does have a purpose; read on to find out what it is!
Compared to a conversion function to bool
, we have avoided the unfortunate overloading issues, and the effects of returning an integral type (making some nonsense constructs legal). We have added the usability that was obscured by operator!
, and disabled the potential delete
issue with operator void*
. Quite impressive! There's one additional twist that makes the solution complete, and that is to disable comparisons between distinct instances of Testable
. With our current implementation, you can write code like this:
Testable test; Testable test2; if (test1==test2) {} if (test!=test2) {}
Comparisons like the above are not only meaningless; they're dangerous, because they imply an equivalence relationship that can never exist between different instances of Testable
. We need to find a way to disable such nonsensical comparisons.
template <typename T> bool operator!=(const Testable& lhs,const T& rhs) { lhs.this_type_does_not_support_comparisons(); return false; } template <typename T> bool operator==(const Testable& lhs,const T& rhs) { lhs.this_type_does_not_support_comparisons(); return false; }
Of course! By defining operator==
and operator!=
as non-members, and having them attempt to call a non-public member (this_type_does_not_support_comparisons
) on the Testable
argument will result in a compile error, thus disallowing tests that don't make sense [3]. (The obvious versions taking Testable
as the second argument are omitted here for brevity.) Using parameterized implementations, we ensure that an error is only emitted if and when a comparison function is instantiated. The long (and fairly descriptive) name of the called member function will definitely be part of the compiler error message if a comparison function is instantiated, making it easy to locate and correct the error. For tests that you do want to allow, simply define the comparison operators as usual.
This, my friends, is the safe bool idiom. When people started using this idiom, it was discovered that there was an efficiency penalty on some compilers — the member function pointer caused a compiler headache resulting in slower execution when the address was fetched. Although the difference is marginal, the current practice is typically to use a member data pointer instead of a member function pointer. [4]
class safe_bool_base { protected: typedef void (safe_bool_base::*bool_type)() const; void this_type_does_not_support_comparisons() const {} safe_bool_base() {} safe_bool_base(const safe_bool_base&) {} safe_bool_base& operator=(const safe_bool_base&) {return *this;} ~safe_bool_base() {} }; template <typename T=void> class safe_bool : public safe_bool_base { public: operator bool_type() const { return (static_cast<const T*>(this))->boolean_test() ? &safe_bool_base::this_type_does_not_support_comparisons : 0; } protected: ~safe_bool() {} }; template<> class safe_bool<void> : public safe_bool_base { public: operator bool_type() const { return boolean_test()==true ? &safe_bool_base::this_type_does_not_support_comparisons : 0; } protected: virtual bool boolean_test() const=0; virtual ~safe_bool() {} }; template <typename T, typename U> void operator==(const safe_bool<T>& lhs,const safe_bool<U>& rhs) { lhs.this_type_does_not_support_comparisons(); return false; } template <typename T,typename U> void operator!=(const safe_bool<T>& lhs,const safe_bool<U>& rhs) { lhs.this_type_does_not_support_comparisons(); return false; }
Here's how to use safe_bool
:
class Testable_with_virtual : public safe_bool<> { protected: bool boolean_test() const { // Perform Boolean logic here } }; class Testable_without_virtual : public safe_bool <Testable_without_virtual> { public: bool boolean_test() const { // Perform Boolean logic here } };
The first class, Testable_with_virtual
, derives publicly from safe_bool
, and implements a virtual function boolean_test
—this function is called whenever an instance is tested (as in if (obj){}
, or if (!obj){}
). The second class, Testable_without_virtual
, also derives publicly from safe_bool
, and in addition, it passes itself as a template parameter to its base class. This little trick—known as the Curiously Recurring Template Pattern— enables the base class to downcast (to the derived class) using static_cast
and call boolean_test
with no extra runtime overhead and no virtual function calls. Some people may feel that this is a slight misuse of inheritance; while it might be argued that an instance of a derived class is-a safe_bool
of sorts, this is certainly not the intent of this code. However, there is little reason to believe that even neophyte programmers will fall into the trap of misunderstanding this relationship. The destructors of the safe_bool
classes are protected to minimize the potential for misuse. But there's still hope for the (in my opinion, overly) conscientious object-oriented purist; use private inheritance, and make the conversion function public by reintroducing it in the correct scope:
class Testable_without_virtual : private safe_bool <Testable_without_virtual> { public: using safe_bool<Testable_without_virtual>::operator safe_bool; bool boolean_test() const { return true; // Logic goes here! } };
Matthew Wilson [5] pointed out that the inheritance strategy (using safe_bool
as a base class) may lead to size penalties on some compilers, specifically, those that do not implement EBO (Empty Base Optimization) properly. Although most modern compilers do when it comes to single inheritance, there may be a size penalty with multiple inheritance.
void*
conversion in iostreams. Do you know which state flags are considered in that test? Most people probably think they do. I looked it up and realized that at least I was wrong—the
eofbit
flag is ignored. This goes to show that if programmers' expectations of the semantics may differ, providing a member function with a descriptive name is much better. In the case of iostreams, it's reasonable to test for errors using
fail()
, and failure of input using
!good()
. For a container class, having a conversion function would be absolutely disastrous, because the possible interpretations of its meaning are so plentiful. For most classes, the proper way to design tests for validity is to provide member functions with clever names, not clever conversion functions. There you go.
Without the work of these people, and others who've come to the same conclusions, chances are that the safe bool idiom would not have seen the light of day.
operator==
and operator!=
was invented by Douglas Gregor, and the technique is sometimes referred to as �poisoning operators�. I've added an (parameterized) implementation that fails to compile (when instantiated) rather than just defining the operators and waiting until link time for the error to appear.Have an opinion? Readers have already posted 17 comments about this article. Why not add yours?
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