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Message:

Initializers are Run When Objects are Created

Posted by Bill Venners on April 21, 2000 at 2:41 PM

> Could you explain to me the logic of the output as given by the foll. program : (I am terribly confused by private Circle c1=new Circle(100); line - When is it executed ???)
> Thanks,
> Radhey
> *************
> import java.util.*;

> class Shape {
> Shape(int i) {
> System.out.println("Shape constructor"+"-->"+i);
> }
> }

> class Circle extends Shape {
> Circle(int i) {
> super(i);
> System.out.println("Drawing a Circle"+"-->"+i);
> }
> }

> public class rss extends Shape {
> private Circle c;
> private Circle c1=new Circle(100);
> rss(int i) {
> super(i + 1);
> c = new Circle(1);
> System.out.println("Combined constructor");
> }
>
> public static void main(String[] args) {
> rss x = new rss(47);
> }
> }

The statement:

private Circle c1=new Circle(100);

is executed when your main() method instantiates the
rss object, becuase c1 is an instance variable of the
rss object, initialized by the new Circle(100) initializer.

bv