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Message:

Answer to your question....

Posted by ruchi and hema on November 12, 2000 at 5:54 AM

hello....

it is very easy to understand this concept....

in case of post increment(a++)..the value of 'a' will be assigned
first and later is will incremented...when u say first time
a++ this will assign the value of 'a'(i.e 1) to 'a'..and late it
will be incremented ..but this is not the case here...The imp
thing to remember here is that in case of post increment if
arithmetic operators are not provided the value will not be
incremented..So the changes of increment r not visible to u..
so here if u change ur code to a=a++ +2 u will see the value
to be 3..i.e the value of a will be assigned first and then
incremented and later u do post increment on that value without
arithmetic operation it will never change..But this is not
the case with pre increment..it will remain the same as we do..
in pre increment arithmetic operators r not required...it will
change the value before assignment.....hope ur doubts will be]
clear.....try out the foll. code..

int a=1;
a=a++;
System.out.println(a);
a=a++ +2;
System.out.println(a);

o/p.......1
3

Thanks....hema and ruchi

I am not able to understand why all the printed answers for a is 1 while it is supposed to increase

> class test3
> {
> public static void main(String s[])
> {
> int a = 1;
> System.out.println(a);
> a=a++;
> System.out.println(a);
>
> a=a++;
> a=a++;
> System.out.println(a);
>
> a=++a;
> System.out.println(a);
> a=++a;
> a=++a;
> System.out.println(a);

> }
> }