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Message:

++ puzzle

Posted by Kishori Sharan on June 08, 2001 at 3:31 PM

int i = 1 ;
i = i ++ ;

1) ( int i = 1 ) : i is initialized to 1
2) ( i = i ++ ) : i++ is evaluated. This makes the expression as
i = 1 because i++ uses post increment operator.
3) Now i is incremented to 2 , that is the effect of post increment operator ++.
4) At this stage the expression i = i++ is in form i = 1 and in memory i has been incremented to 2.
5) Now i = 1 is executed which makes i equla to 1.\
6) Finally i is 1 after i = i++ is executed.

The important thing to remember is that in i++ , first the value of i is substituted in place of i++ and then i is incremented immediately . Java dosn't wait to inclrement the value of i util i = i++ whole expression is executed.

Thanks
Kishori