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About operation"+++++"

2 replies on 1 page. Most recent reply: May 8, 2003 6:16 AM by James Patterson

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Saint Jerry

Posts: 1
Nickname: pretender
Registered: May, 2003

About operation"+++++"

Posted: May 5, 2003 10:06 PM

There is a simple program but that is too diffeicult
for me to think out.Please explain it to me.

public class One{
public static void main(String args[]){
int i=1,j;
j=i+++++i;
System.out.println("i="+i+" j="+j);
}
}
Why this program can not pass compiler? But when I
change this sentence "j=i+++++i" to "j=(i++)+(++i)" or
"j=i+++(++i)",I just can get the right result. However
I cannot pass compiler as I change "j=i+++++i" to
"j=(i++)+++i". Why?

Matt Gerrans

Posts: 1153
Nickname: matt
Registered: Feb, 2002

Re: About operation"+++++"

Posted: May 5, 2003 10:13 PM

Why do you want to write such horrible stuff? Even if you get some variation of this to work, it just makes for code that confuses the reader. The purpose of code is to comunicate to other people, otherwise we'd all just write machine code instead of easier-to-understand languages like Java, Python, C#, etc.

James Patterson

Posts: 16
Nickname: jmep
Registered: Mar, 2003

Re: About operation"+++++"

Posted: May 8, 2003 6:16 AM

i+++++i is too ambiguous. exp++ has a higher precedence than ++exp and +. Therefore your compiler will see something like (i++)++ + i and this is invalid syntax. However, if you use i+++(++i) then it sees i++ + ++i because you are forcing the ++i grouping to be seen first and it can figure out i+++.

See: http://java.sun.com/docs/books/tutorial/java/nutsandbolts/expressions.html

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