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Re: Float Compare
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Posted: Jul 8, 2002 7:24 PM
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> Hi
>
> Why the below code always evaluate to be true/0?
> Can anybody tell me how to do it correctly
>
> Float f= new Float (999999.99f);
> Float f2 = new Float(1000000.00f);
>
> System.out.println(f.compareTo(f2));
> System.out.println(f.floatValue()==
> = f2.floatValue());
Java uses IEEE format to store float and double values in memor 0.99 cannot be represented in binary in finite number of bits , so Java uses the closest value instead of exact one. And, in your case 999999.99f is closest to 1000000.00f. Therefore, both values are stored as 1000000.00f inside.
Thanks
Kishori
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