Java Answers Forum - exception handling

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exception handling

2 replies on 1 page. Most recent reply: Jul 31, 2002 4:48 PM by Thomas SMETS

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Vanna Nguyen

Posts: 3
Nickname: vanilla
Registered: Jul, 2002

exception handling

Posted: Jul 28, 2002 10:54 AM

explain the strange behavior of below method:
void strange() throws Exception {
try {
throw new Exception ("firstException");
}
finally {
System.out.println("finally is executed");
throw new Exception("second exception");
}
}

thomas

Posts: 42
Nickname: turbomanic
Registered: Jul, 2002

Re: exception handling

Posted: Jul 28, 2002 11:21 AM

Dont throw an exception in the try statement. You must catch the exception in the catch statement and tell the computer what then to do with it.

Thomas SMETS

Posts: 307
Nickname: tsmets
Registered: Apr, 2002

Re: exception handling

Posted: Jul 31, 2002 4:48 PM

What don't you understand ?

  try 
  {
    System.out.println ("Before throwing an Exception");
    throw new Exception ("firstException");
  } finally 
  {
    System.out.println ("finally is executed");
    throw new Exception ("second exception");
  }

Running the code you should get :

Before throwing an Exception.
finally is executed

AFAIK only the first Exception should be visible, not the second.

Thomas SMETS,

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